Calling all you math heads, answer me this!
#92
Calling all you math heads, answer me this!
Originally posted by: Knutz
OK Bryce,
This third party on some other forum must be the expert. There is no way I could possibly have a bit more experience or knowledge on the subject. Heck, by that matter, your knowledge about the subject must be far superior to mine.
It's not worth the pissing match. If you were as intelligent as I thought you were, you would know that the closest your comeing with your math is an approximation. Instead, you want to insist that your exact and correct, seamingly out of silly spite. Whatever.
I guess that assumptions must make for exact answers, till now, I never realized that. Thanks for the education.
Could you please explain one last thing though, if the top speed is measured by calculating the time to cover the last 66' of the track, how are you calculating exact possition down to the foot? Please continue to teach me.
OK Bryce,
This third party on some other forum must be the expert. There is no way I could possibly have a bit more experience or knowledge on the subject. Heck, by that matter, your knowledge about the subject must be far superior to mine.
It's not worth the pissing match. If you were as intelligent as I thought you were, you would know that the closest your comeing with your math is an approximation. Instead, you want to insist that your exact and correct, seamingly out of silly spite. Whatever.
I guess that assumptions must make for exact answers, till now, I never realized that. Thanks for the education.
Could you please explain one last thing though, if the top speed is measured by calculating the time to cover the last 66' of the track, how are you calculating exact possition down to the foot? Please continue to teach me.
It seems that I and others have said multiple times that we know that this only an approximation. I have never said my answer is exact. However if you are looking for an answer to a math problem, given the assumption that the acceleration is constant in the last 1/8; my solution is correct.
I did not calculate the acceleration by looking at the time to cover the last 66 feet. The only one that said he calculated to the foot was the guy with the speadsheet. My calculation says that the acceleration is constant over the last 1/8 mile.
I do not see this as a pissing match, I see it only as a discussion.
#93
Calling all you math heads, answer me this!
Two guys walk into a bar, the third one ducks! [img]i/expressions/face-icon-small-happy.gif[/img] [img]i/expressions/face-icon-small-happy.gif[/img] [img]i/expressions/face-icon-small-happy.gif[/img] [img]i/expressions/face-icon-small-happy.gif[/img]
#94
Calling all you math heads, answer me this!
Originally posted by: BryceGTX
I would like to hear your version of the acceleration process of a fueler. I expect it will support what is said on the dragster forums.
It seems that I and others have said multiple times that we know that this only an approximation. I have never said my answer is exact. However if you are looking for an answer to a math problem, given the assumption that the acceleration is constant in the last 1/8; my solution is correct.
I did not calculate the acceleration by looking at the time to cover the last 66 feet. The only one that said he calculated to the foot was the guy with the speadsheet. My calculation says that the acceleration is constant over the last 1/8 mile.
I do not see this as a pissing match, I see it only as a discussion.
Originally posted by: Knutz
OK Bryce,
This third party on some other forum must be the expert. There is no way I could possibly have a bit more experience or knowledge on the subject. Heck, by that matter, your knowledge about the subject must be far superior to mine.
It's not worth the pissing match. If you were as intelligent as I thought you were, you would know that the closest your comeing with your math is an approximation. Instead, you want to insist that your exact and correct, seamingly out of silly spite. Whatever.
I guess that assumptions must make for exact answers, till now, I never realized that. Thanks for the education.
Could you please explain one last thing though, if the top speed is measured by calculating the time to cover the last 66' of the track, how are you calculating exact possition down to the foot? Please continue to teach me.
OK Bryce,
This third party on some other forum must be the expert. There is no way I could possibly have a bit more experience or knowledge on the subject. Heck, by that matter, your knowledge about the subject must be far superior to mine.
It's not worth the pissing match. If you were as intelligent as I thought you were, you would know that the closest your comeing with your math is an approximation. Instead, you want to insist that your exact and correct, seamingly out of silly spite. Whatever.
I guess that assumptions must make for exact answers, till now, I never realized that. Thanks for the education.
Could you please explain one last thing though, if the top speed is measured by calculating the time to cover the last 66' of the track, how are you calculating exact possition down to the foot? Please continue to teach me.
It seems that I and others have said multiple times that we know that this only an approximation. I have never said my answer is exact. However if you are looking for an answer to a math problem, given the assumption that the acceleration is constant in the last 1/8; my solution is correct.
I did not calculate the acceleration by looking at the time to cover the last 66 feet. The only one that said he calculated to the foot was the guy with the speadsheet. My calculation says that the acceleration is constant over the last 1/8 mile.
I do not see this as a pissing match, I see it only as a discussion.
#95
Calling all you math heads, answer me this!
Originally posted by: BryceGTX
t = 4.31348 seconds is when the dragster passes the Nascar
S = 0.05555 * t = 0.2396 mile = 1265 feet
Bryce
t = 4.31348 seconds is when the dragster passes the Nascar
S = 0.05555 * t = 0.2396 mile = 1265 feet
Bryce
You did not use the time for the last 66' to calculate the speed, the speed was given in the word problem. The issue arises in the fact that drag racing trap speeds are calculated this way, hence the are simply an average speed over that distance, not taking acceleration into account. It's just one more factor that makes a true answer impossible to achieve, only an approximation.
Now, if you could get into the computer and get the exact time that it entered the "traps" and the exact time it exited, your approximation would be much closer. Unfortunatly, we have no times at all for the dragster, and no sure way to get them, so a close guess is as close as anyone could come.
*edit* I went back and noticed that the top fuel record time was added to the original post, so I stand corrected about no times at all. Still, without supporting times such as reaction times, it's still a guess.
#96
Calling all you math heads, answer me this!
Originally posted by: Knutz
That sure looks down to the foot to me.
You did not use the time for the last 66' to calculate the speed, the speed was given in the word problem. The issue arises in the fact that drag racing trap speeds are calculated this way, hence the are simply an average speed over that distance, not taking acceleration into account. It's just one more factor that makes a true answer impossible to achieve, only an approximation.
Now, if you could get into the computer and get the exact time that it entered the "traps" and the exact time it exited, your approximation would be much closer. Unfortunatly, we have no times at all for the dragster, and no sure way to get them, so a close guess is as close as anyone could come.
*edit* I went back and noticed that the top fuel record time was added to the original post, so I stand corrected about no times at all. Still, without supporting times such as reaction times, it's still a guess.
Originally posted by: BryceGTX
t = 4.31348 seconds is when the dragster passes the Nascar
S = 0.05555 * t = 0.2396 mile = 1265 feet
Bryce
t = 4.31348 seconds is when the dragster passes the Nascar
S = 0.05555 * t = 0.2396 mile = 1265 feet
Bryce
You did not use the time for the last 66' to calculate the speed, the speed was given in the word problem. The issue arises in the fact that drag racing trap speeds are calculated this way, hence the are simply an average speed over that distance, not taking acceleration into account. It's just one more factor that makes a true answer impossible to achieve, only an approximation.
Now, if you could get into the computer and get the exact time that it entered the "traps" and the exact time it exited, your approximation would be much closer. Unfortunatly, we have no times at all for the dragster, and no sure way to get them, so a close guess is as close as anyone could come.
*edit* I went back and noticed that the top fuel record time was added to the original post, so I stand corrected about no times at all. Still, without supporting times such as reaction times, it's still a guess.
#97
Calling all you math heads, answer me this!
Originally posted by: OneFlyCowboy
yup thats me [img]i/expressions/face-icon-small-happy.gif[/img] and in order for the distances to be covered in the amount of time available and accelerate from the 268 to the 336 certain things have to take place.. Now if you tell me that the car actually travels faster than the top speed at the end of thetrack. well then i could be wrong.
yup thats me [img]i/expressions/face-icon-small-happy.gif[/img] and in order for the distances to be covered in the amount of time available and accelerate from the 268 to the 336 certain things have to take place.. Now if you tell me that the car actually travels faster than the top speed at the end of thetrack. well then i could be wrong.
The car doesn't travel faster than the top speed, but the simple formulations used, assume that it's doing 302MPH at 3/16th of a mile, when it likely is not. Due to the downward curve of acceleration at that point, it's actually traveling faster than the 302MPH assumed.
*edit* If we want to talk reality, the reported top speed of the car is not the actuall top speed, but an average speed for the last 66'. So it actually enters the traps at one speed, exits at another due to acceleration, and an average of the two is what's reported. It is done this way because it's the most acurate way to measure the speed at the finish, but is not 100% correct. It is close enough for racing purposes though, and since all drag races are measured this way, it offers a standard basis for compairison.
#98
Calling all you math heads, answer me this!
Originally posted by: Knutz
What is the amount of time to accelerate from 268 to 336, and how did you get that time?
The car doesn't travel faster than the top speed, but the simple formulations used, assume that it's doing 302MPH at 3/16th of a mile, when it likely is not. Due to the downward curve of acceleration at that point, it's actually traveling faster than the 302MPH assumed.
*edit* If we want to talk reality, the reported top speed of the car is not the actuall top speed, but an average speed for the last 66'. So it actually enters the traps at one speed, exits at another due to acceleration, and an average of the two is what's reported. It is done this way because it's the most acurate way to measure the speed at the finish, but is not 100% correct. It is close enough for racing purposes though, and since all drag races are measured this way, it offers a standard basis for compairison.
Originally posted by: OneFlyCowboy
yup thats me [img]i/expressions/face-icon-small-happy.gif[/img] and in order for the distances to be covered in the amount of time available and accelerate from the 268 to the 336 certain things have to take place.. Now if you tell me that the car actually travels faster than the top speed at the end of thetrack. well then i could be wrong.
yup thats me [img]i/expressions/face-icon-small-happy.gif[/img] and in order for the distances to be covered in the amount of time available and accelerate from the 268 to the 336 certain things have to take place.. Now if you tell me that the car actually travels faster than the top speed at the end of thetrack. well then i could be wrong.
The car doesn't travel faster than the top speed, but the simple formulations used, assume that it's doing 302MPH at 3/16th of a mile, when it likely is not. Due to the downward curve of acceleration at that point, it's actually traveling faster than the 302MPH assumed.
*edit* If we want to talk reality, the reported top speed of the car is not the actuall top speed, but an average speed for the last 66'. So it actually enters the traps at one speed, exits at another due to acceleration, and an average of the two is what's reported. It is done this way because it's the most acurate way to measure the speed at the finish, but is not 100% correct. It is close enough for racing purposes though, and since all drag races are measured this way, it offers a standard basis for compairison.
--------------------------------Top-Fuel-Dragster
--------Time-SC Dist----Distance-ft/sec-Speed-mph
---------3.05---894.67--660.00--393.07--268.00
---------3.10---909.33--680.10--402.05--274.13
---------3.15---924.00--700.65--411.03--280.25
---------3.20---938.67--721.66--420.02--286.38
---------3.25---953.33--743.11--429.00--292.50
---------3.30---968.00--765.00--437.98--298.63
---------3.35---982.67--787.35--446.97--304.75
---------3.40---997.33--810.15--455.95--310.88
---------3.45--1012.00--833.40--464.93--317.00
---------3.50--1026.67--857.09--473.92--323.13
---------3.55--1041.33--881.24--482.90--329.25
---------3.60--1056.00--905.89--493.02--336.15
---------3.65--1070.67--930.54--493.02--336.15
---------3.70--1085.33--955.19--493.02--336.15
---------3.75--1100.00--979.84--493.00--336.15
---------3.80--1114.67-1004.49--493.00--336.15
---------3.85--1129.33-1029.14--493.00--336.15
---------3.90--1144.00-1053.79--493.00--336.15
---------3.95--1158.67-1078.44--493.00--336.15
---------4.00--1173.33-1103.09--493.00--336.15
---------4.05--1188.00-1127.74--493.00--336.15
---------4.10--1202.67-1152.39--493.00--336.15
---------4.15--1217.33-1177.04--493.00--336.15
---------4.20--1232.00-1201.69--493.00--336.15
---------4.25--1246.67-1226.34--493.00--336.15
---------4.30--1261.33-1250.99--493.00--336.15
---------4.35--1276.00-1275.64--493.00--336.15
--------4.351--1276.29-1276.13--493.00--336.15
--------4.352--1276.59-1276.63--493.00--336.15
--------4.353--1276.88-1277.12--493.00--336.15
--------4.354--1277.17-1277.61--493.00--336.15
--------4.355--1277.47-1278.11--493.00--336.15
--------4.356--1277.76-1278.60--493.00--336.15
--------4.357--1278.05-1279.09--493.00--336.15
--------4.358--1278.35-1279.58--493.00--336.15
--------4.359--1278.64-1280.08--493.00--336.15
---------4.36--1278.93-1280.57--493.00--336.15
---------4.37--1281.87-1285.50--493.00--336.15
---------4.38--1284.80-1290.43--493.00--336.15
---------4.39--1287.73-1295.36--493.00--336.15
---------4.40--1290.67-1300.29--493.00--336.15
---------4.41--1293.60-1305.22--493.00--336.15
---------4.42--1296.53-1310.15--493.00--336.15
---------4.43--1299.47-1315.08--493.00--336.15
---------4.44--1302.40-1320.00--493.00--336.15
---------4.45--1305.33
---------4.50--1320.00
#99
Calling all you math heads, answer me this!
Column Titles
Time = Time on the track
SC Dist = Stock Cars position on the track at given time
Distance = Top fuels position on the track at given time
Ft/sec = how many feet per second the Top fuel is traveling
Speed MPH = Of course how many MPH the top fuel is going
Soo has you can see the amount of ground that must be covered by the car in the last 660 feet of the track maximum speed must be reached for that run at the 905' mark on the track. everything else is just what it is.
Time = Time on the track
SC Dist = Stock Cars position on the track at given time
Distance = Top fuels position on the track at given time
Ft/sec = how many feet per second the Top fuel is traveling
Speed MPH = Of course how many MPH the top fuel is going
Soo has you can see the amount of ground that must be covered by the car in the last 660 feet of the track maximum speed must be reached for that run at the 905' mark on the track. everything else is just what it is.
#100
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Resident Killer!
"A little nonsense now and then, is relished by the wisest men". Willy Wonka: 1971
Cigars! Earth ne'eer did breed such a jovial weed.
A Tiger Doesn't Lose Sleep Over Opinions of Sheep
Resident Killer!
"A little nonsense now and then, is relished by the wisest men". Willy Wonka: 1971
Cigars! Earth ne'eer did breed such a jovial weed.
A Tiger Doesn't Lose Sleep Over Opinions of Sheep
Joined: Jan 2006
Posts: 54,748
Likes: 5
From: Landrum, South Carolina, elevation 986'
Calling all you math heads, answer me this!
Actually any approximate answer will be correct as a drag car never runs "or extremely rare" the same times more than once. =]
I guess you can say our answers are as accurate as when they try to figure collateral damage for nuclear devices. It's imposable to have an accurate body count, but it's fun as héll to figure out. lol. =]
I guess you can say our answers are as accurate as when they try to figure collateral damage for nuclear devices. It's imposable to have an accurate body count, but it's fun as héll to figure out. lol. =]