I was wondering if we change the timing curve and gain horsepower is the toque curve moving up as well. When the long awaited soon to be out, delayed again, coming next month, who knows when CDI box arrives, will the low end torque still be there when I need it? More power is good, but more torque is better.


03 P-650
DG Holeshot
DG Snorkel
K&N Filter
Headlight mod
Primary Dalton Plain\white spring
Secondary EPI black spring
ITP 589's on C's
Warn 2500 winch
Rear backup light
(On order) Dial-A-Jet

 

In your example, yes, unless you change your shift out rpm, in which case, all bets are off. For example, if you made 40 lb/ft at 6100 stock, your bhp would be 46. Move that rpm to 5800, and voila! You now have less bhp. I think the question we should be asking of these companies that manufacture products is more related to "how much power does (pick a mod) it make under the curve?"

 

Engines do not create "horse power". Horse power is a mathematical equation, a measurement of of torque and speed..

Torque * RPM

Horsepower = ------------

5252

For purposes of this discussion, we need to measure units of force from rotating objects such as crankshafts, so we'll use terms which define a *twisting* force, such as foot pounds of torque. A foot pound of torque is the twisting force necessary to support a one pound weight on a weightless horizontal bar, one foot from the fulcrum.

Now, it's important to understand that nobody on the planet ever actually measures horsepower from a running engine. What we actually measure (on a dynomometer) is torque, expressed in foot pounds (in the U.S.), and then we *calculate* actual horsepower by converting the twisting force of torque into the work units of horsepower.

Visualize that one pound weight we mentioned, one foot from the fulcrum on its weightless bar. If we rotate that weight for one full revolution against a one pound resistance, we have moved it a total of 6.2832 feet (Pi * a two foot circle), and, incidently, we have done 6.2832 foot pounds of work.

OK. Remember Watt? He said that 33,000 foot pounds of work per minute was equivalent to one horsepower. If we divide the 6.2832 foot pounds of work we've done per revolution of that weight into 33,000 foot pounds, we come up with the fact that one foot pound of torque at 5252 rpm is equal to 33,000 foot pounds per minute of work, and is the equivalent of one horsepower. If we only move that weight at the rate of 2626 rpm, it's the equivalent of 1/2 horsepower (16,500 foot pounds per minute), and so on. Therefore, the following formula applies for calculating horsepower from a torque measurement:

you can check out the whole primer at
Horse Power VS Torque

 

Dang, I just broke my calculator!

 

i remember reading something (that mostly went way over my head) that said no matter how much torqe or horse power your engine has the lines will cross (if expressed on a graph) ie you will have an equal amout of torque and hp at a specific rpm and no matter what you do to your engine or what engine you have the hp will meet the Torque at that rpm,

just wondering if its 5252 rpm??

 

i think i hemoraged my madula oblonggata. (spelling???) you know what i mean.

 

lol...better watch out someone might be a little grouchy from now on!

ohh and as far as the calculations go... I learned that in 9th grade...for the most part. I understand what he is sayin...I think some people need to go back to school while I need out!

 

Yes ... 5252 rpm is the point where Horse power and torque will be equal.

Torque is what you "feel"... torque is what lifts the front end of your quad off the ground ....

The goal is to produce more torque and a higher RPM.

If you have made modifications that truly are producing more torque at higher rpm, (more HP)
you should be able to witness that by the fact that the quad will lift the wheels at a higher speed.
(talkin V force here ...) or quicker times in a predetermined distance.

So , If you have more torque at a higher speed with a manual transmission , you can shift at a higher rpm to make use of that. If you have a quad with a CVT transmission .... you need to change the spring(s) and or wieghts to allow it rev to the higher rpm, then begin to shift out process.

If you don't change the clutch shift out rpm, the result will be as if you are "short shifting" a manual quad. you will not feel all of the addition torque available.



Just my Two Cents......